So, what is the value of i? The value of I is √-1. The imaginary unit number, where I stands for imaginary or unit imaginary, expresses complex numbers. We will go through the principles and chart for imaginary numbers, which are employed in mathematical computations.

Calculators can perform basic arithmetic operations on complex numbers. Sometimes the imaginary number I is written as j. When there is a negative number inside the square root, the square of an imaginary number equals the root of -1, the value of imaginary i is formed.

The value of the cube of I, on the other hand, is -i. It’s a solution to the quadratic equation x2 1 = 0, such as;

x2 = 0 – 1

x2 = -1

x = √-1

x = *i*

As a result, an imaginary number is a subset of a complex number that can be written as a real number multiplied by the imaginary unit I with *i*2 = -1. When the imaginary number is multiplied by itself, the result is negative.

Consider the imaginary number 3i, which yields 9*i*2 or -9 when multiplied by itself or when the square of 3i is taken. Moreover, 0 is regarded as both a real and an imaginary number.

This circular formula is used to calculate the value of higher degrees of i. Mathematics is a discipline that is both intellectual and practical. It does not encourage the acquisition of values. Understanding the ideas will help you better grasp mathematical applications.

The study of complex numbers is a vital subject. A big element of it is the idea of imaginary numbers.

**Values of i**

Because we know that *i*2 = -1, we can determine the value of I when raised to the power of other imaginary numbers.

i3 | i2 * i | -i |

i4 | i2 * i2 = -1 * -1 | 1 |

i5 | i2 * i2 * i | i |

i6 | i2 * i2* i2 | −1 |

i0 | i1-1 = i1.i-1 = i1/i = i/i =1 | 1 |

i−1 | 1/-i = -i/(-i)2 = -i/1 | −i |

i−2 | 1/i2 | −1 |

i−3 | 1/i3=1/-i=i/(-i)2 | i |

The power of I, as seen in the table above, repeats in a cycle, as follows:

i4n = 1

i4n 1 = i

i4n 2= -1

i4n 3=-I

and so forth.

Let’s look at several cases where the value of I is important.

**Solve x***2*** 16 = 0**

Solution: x*2* 16 = 0

x*2*= -16

x =√-16

x = i √16

x = i4

**Check: **

L.H.S = x*2* 16 = (i4)*2* 16 = i*2*4*2* 16 = -16 16 = 0 (R.H.S)

**Iota’s Higher Powers**

Higher powers of iota can be determined by dividing the larger exponents I into smaller ones and evaluating the equation. Using the previous approach to get value if the power of iota is a greater number will require a long time and effort.

We can compute the value of iota for higher powers by looking at all the powers of iota and the pattern in which they repeat their values in the equations above.

**Step 1: **Take the supplied power and divide it by four.

**Step 2: **Write down the residue from Step 1’s division and use it as the new exponent/power of iota.

**Step 3:** Using the previously calculated numbers, calculate the value of iota for this new exponent/power. i*i* = √−1; i*i*2 = -1 and i*i*3 = -i*i*.

**Iota Value for Negative Power**

A few procedures may be used to compute the iota value for negative power. We use the negative exponent law to transform it to a positive exponent, and then we use the rule: 1/i*i* = -i*i*. This is because:1/i*i* = 1/i*i* • i*i*/i*i* = i*i*/i*i*2 = i*i*/(-1) = -i*i*

**Conclusion**

The idea of i or the value i is used to understand and represent complex numbers. Complex numbers are those that have both a real and an imaginary component. With the assistance of i, the imaginary component is defined. I stand for the imaginary portion, often known as iota.

The value of I is √-1. An imaginary value is represented as a negative value within a square root. Imaginary numbers may use all of the standard arithmetic operators. We get a negative result when we square an imaginary integer.

- i
*i*= √−1 is the value of iota. - i2 = −1 is the value of the square of iota.
- √i
*i*= √2/2 i*i*√2/2 is the value of the square root of iota.